You arrive at your school 5 minutes late if you walk with a speed of 4 km/hr, but you arrive 10 minutes before the scheduled time if you walk with a speed of 5 km/hr. The distance of your school from your house is :
You arrive at your school 5 minutes late if you walk with a speed of 4 km/hr, but you arrive 10 minutes before the scheduled time if you walk with a speed of 5 km/hr. The distance of your school from your house is :
[A]2 km
[B]4 km
[C]5 km
[D]10 km
5 km
If the required distance be x km, then
$latex \frac{x}{4} – \frac{x}{5} = \frac{10+5}{60}&s=1$
$latex => \frac{5x – 4x}{20} = \frac{1}{4}&s=1$
$latex => \frac{x}{20} = \frac{1}{4}&s=1$
$latex => x = \frac{1}{4}\times 20 = 5\ km&s=1$
Hence option [C] is correct answer.