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A man rides at the rate of 18 km/hr, but stops for 6 minutes to change horses at the end of every 7th km. The time that he will take to cover a distance of 90 km is :

A man rides at the rate of 18 km/hr, but stops for 6 minutes to change horses at the end of every 7th km. The time that he will take to cover a distance of 90 km is :
[A]6 hours
[B]6 hours 12 minutes
[C]6 hours 18 minutes
[D]6 hours 24 minutes

6 hours 12 minutes
90 km = 12 \times 7 km + 6 km.
To cover 7 km total time taken = \frac{7}{18} hours + 6 min. = \frac{88}{3}\ min.
So, (12 \times 7 km) would be covered in \left ( 12\times \frac{88}{3} \right ) minutes and remaining 6 km is \frac{6}{18} hours or 20 miutes.
∴ Total time = \frac{1056}{3}+20 = \frac{1116}{3\times 60} = 6\frac{1}{5} \ hours
= 6 hours 12 minutes.
Hence option [B] is correct answer.

Originally written on August 30, 2016 and last modified on August 30, 2016.
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